Question

若函数f(x)满足f(x+y)=f(x)+f(y)(x,y属于R),则下列等式不衡成立的是

Answer 1

f(0)=f(0+0)=f(0)+f(0)

f(0)=0

f(3)=f(2+1)=f(2)+f(1)=f(1+1)+f(1)=3f(1)

f(1)=f(0.5+0.5)=2f(0.5)

f(0.5)=0.5f(1)

f(0)=f((-x)+f(x))=f(-x)+f(x)=0

f(-x)=-f(x)

f（-x)f(x)=-(f(-x))^2