Question

已知函数f(x）当x属于（负无穷,0),f(x)=1/x,当x属于【0,正无穷),f(x)=x^2,求f(x+1)

Answer 1

当x+1属于（负无穷,0),即x属于（负无穷,-1）时,f(x+1)=1/（x+1）,

当x+1属于【0,正无穷),即x属于【-1,正无穷）时,f(x+1)=（x+1）^2,

所以 f(x)={1/（x+1）,x=-1.