求函数f(x)=(3+5sinx)/√(5+4cosx+3sinx)的值域

1个回答

  • 关键是化成半角sinx=2sin(x/2)*cos(x/2) cosx=cos^2(x/2)-sin^2(x/2)

    原式分子=3sin^2(x/2)+3cos^2(x/2)+10sin(x/2)cos(x/2)

    =[sin(x/2)+3cos(x/2)][3sin(x/2)+cos(x/2)]

    分母=5sin^2(x/2)+5cos^2(x/2)+4cos^2(x/2)-4sin^2(x/2)+6sin(x/2)*cos(x/2) 的开平方

    =| 3cos(x/2)+sin(x/2) |

    则原式=+- 10^0.5[cos(x/2 - a)]

    过程自己完善一下