Zn + 2H2SO4浓 = ZnSO4 + SO2 + 2H2O
2X X
Zn + H2SO4稀 = ZnSO4 + H2
y y
n(H2SO4)=18.3mol/L*0.1L=1.83mol
n(SO2)=22.2/22.4=1mol
n(H2SO4浓)=2*1=2mol
n(H+)=1mol/L*1=1mol
所以n(剩H2SO4)=1/2=0.5mol
所以n(用H2SO4)=1.83-0.5=1.33
2x+y=1.33
x+y=1
可得x≈0.33,y≈0.66
x:y=1:2
VSO2/VH2=nSO2/nH2=0.33/0.66=1/2