题目是利用对称区间上的函数的奇偶性求定积分

1个回答

  • 因为f(x)=(sinx)^4=(-sinx)^4=f(-x)

    所以f(x)是偶函数

    π/2 π/2

    ∫ ()dx

    -π/2 0

    2∫4(sinx)^4 xdx=8∫(sinx)^4 xdx

    (sinx)^4

    = (sinx^2)^2

    = ((1 - cos2x)/2)^2

    = (1 - 2cos2x + (cos2x)^2)/4

    = 0.25 - 0.5cos2x + 0.125(1 + cos4x)

    = (cos4x)/8 - (cos2x)/2 + 3/8

    8∫ (sinx)^4dx

    = 8∫ ((cos4x)/8 - (cos2x)/2 + 3/8)dx

    = 8∫ ((cos4x)/8)dx - 8∫ ((cos2x)/2)dx + 8∫ (3/8)dx

    = (1/4)∫ cos4xd4x - 2∫ cos2xd2x + 3x

    = (sin4x)/4 - 2sin2x + 3x + C

    f(π/2)-f(0)=3/2π