已知R1=3kΩ,R2=6kΩ,电压表的内阻为9kΩ,当电压表接在R1两端时,读数为2V,而当电压表接在R2两端的读数为

3个回答

  • 电压表与R1并联的等值电阻 R1'=3k*9k/(3k+9k)=2.25kΩ

    电压表与R2并联的等值电阻 R2'=6k*9k/(6k+9k)=3.6kΩ

    设所求电压为U

    电压表接在R1两端时:

    2/U=2.25k/(2.25k+6k+R3)=2.25k/(8.25k+R3).

    电压表接在R2两端时:

    3.6/U=3.6k/(3k+3.6k+R3)=3.6k/(6.6k+R3)

    即1/U=1k/(6.6k+R3).

    由.两式解得

    R3=6.6kΩ

    U=13.2V