Question

一块铁块浸没在盛满酒精的烧杯中,从杯中溢出8g酒精,现把它放在装满水的烧杯中,将溢出多少水铁块重多少N

Answer 1

F浮=ρ液gV排

8=0.8*10*V排

V排=10cm^3

m水=ρ液V排

=1*10

=10g

G水=m水g

=0.01*10

=0.1N

G铁=ρ铁gV铁

=0.079*10】

=0.79N