Question

（a减b)的2n减1次幂加2（b减a)的2n次幂加(a减b)的2n加1

Answer 1

（a减b)的2n减1次幂加2（b减a)的2n次幂加(a减b)的2n加1

=(a-b)^2n-1+2(a-b)^2n+(a-b)^2n+1

=(a-b)^2n-1[1^2+2(a-b)+(a-b)^2n]

=(a-b)^2n-1(a-b+1)