Question

用适当的方法解一元二次方程9（x+2）²=16 /（x+1）（x-2）=4/2x+6=（x+3）²/

Answer 1

1.（x+2)^2=16/9,x+2=+-4/3,所以x=-2+4/3=-3/2或x=-2-4/3=-10/3;

2.x^2-x-2=4,x^2-x-6=0 ,(x-3)(x+2)=0 x=3或x=-2;

3.2x+6=x^2+6x+9,x^2-4x+3=0,(x-1)(x-3)=0 ,x=1 or x=3;

4.x^2-4x+4=4x^2+12x+9,3x^2+16x+5=0,(3x+1)(x+5)=0 ,x=-1/3 or x=-5