化简①sin（π+α）×cos（3π/α）+sin

化简①sin（π+α）×cos（3π/α）+sin（π/2+α）×cos（π+α）

1个回答

(1)-sina*(-cosa)+cosa*(-cosa)=sinacosa-(cosa)^2
(2)sinx*cosx/(-tanx)*(1/tanx)*(1/tanx)*(-sinx)=(cosx)^4/sinx

化简[sin(π/2-α）cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π
化简[sin(π/2+α)*cos(π/2-α)]/cos(π+α)+[sin(π-α)*cos(π/2+α)]/sin
化简：（Ⅰ）sin(α−2π)cos(α+π)tan(α−99π)cos(π−α)sin(3π−α)sin(−α−π)；
化简sin(2π−α)cos(π+α)cos(π−α)sin(3π−α)sin(−α−π)=−1sinα−1sinα．
化简 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc
化简：sin(3π+α)•cos(π−α)•tan(3π2+α)cos(π3)•sin(π2−α)•cos(−α)=__
（1）化简：sin(2π−α)cos(π+α)cos(3π2+α)cos(13π2−α)cos(π−α)sin(3π−α
化简（1）tan(π−α)cos(2π−α)sin(−α+3π2)cos(−α−π)sin(−π−α)．
化简：tan(π+α)cos(2π+α)sin(α−3π2)cos(−α−3π)sin(−3π−α)=______．
化简：（1）cos(α+π)sin(−α)cos(−3π−α)sin(−α−4π)（2）cos(α−π2)sin(5π2