Question

已知tan（π/4+θ）+tan（π/4-θ)=4,且-π＜θ＜-π/2,求sin²θ-2sinθcosθ-c

Answer 1

tan( π/4 + θ ) + tan( π/4 - θ ) = 4

[ sin( π/4 + θ )cos( π/4 - θ ) + cos( π/4 + θ )sin( π/4 - θ )] / [cos( π/4 + θ )cos( π/4 - θ )] = 4

sin( π/2 ) / [cos( π/4 + θ )cos( π/4 - θ )] = 4

cos( π/4 + θ )cos( π/4 - θ ) = 1 / 4

( cos π/2 + cos 2θ ) / 2= 1 / 4

cos 2θ = 1 / 2

sin 2θ = √( 1 - cos² 2θ ) = √3 / 2

sin² θ - 2sin θ cos θ - cos² θ = - ( sin 2θ + cos 2θ ) = - (√3 + 1) / 2